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4b^2-12b-72=0
a = 4; b = -12; c = -72;
Δ = b2-4ac
Δ = -122-4·4·(-72)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-36}{2*4}=\frac{-24}{8} =-3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+36}{2*4}=\frac{48}{8} =6 $
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